(x+5)(x+7)=(x+1)(x+19)

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Solution for (x+5)(x+7)=(x+1)(x+19) equation: 



(x+5)(x+7)=(x+1)(x+19)

We move all terms to the left:

(x+5)(x+7)-((x+1)(x+19))=0

We multiply parentheses ..

(+x^2+7x+5x+35)-((x+1)(x+19))=0



We calculate terms in parentheses: -((x+1)(x+19)), so:

(x+1)(x+19)

We multiply parentheses ..

(+x^2+19x+x+19)

We get rid of parentheses

x^2+19x+x+19

We add all the numbers together, and all the variables

x^2+20x+19

Back to the equation:

-(x^2+20x+19)



We get rid of parentheses

x^2-x^2+7x+5x-20x+35-19=0

We add all the numbers together, and all the variables

-8x+16=0

We move all terms containing x to the left, all other terms to the right

-8x=-16

x=-16/-8

x=+2

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