(x-18)(x+5)=0

Solution for (x-18)(x+5)=0 equation:

(x-18)(x+5)=0

We multiply parentheses ..

(+x^2+5x-18x-90)=0

We get rid of parentheses

x^2+5x-18x-90=0

We add all the numbers together, and all the variables

x^2-13x-90=0

a = 1; b = -13; c = -90;
Δ = b2-4ac
Δ = -132-4·1·(-90)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-23}{2*1}=\frac{-10}{2}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+23}{2*1}=\frac{36}{2}
=18
$