4(x+3)+18-x=2(-x+5)+5

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Solution for 4(x+3)+18-x=2(-x+5)+5 equation: 



4(x+3)+18-x=2(-x+5)+5

We move all terms to the left:

4(x+3)+18-x-(2(-x+5)+5)=0

We add all the numbers together, and all the variables

4(x+3)-x-(2(-1x+5)+5)+18=0

We add all the numbers together, and all the variables

-1x+4(x+3)-(2(-1x+5)+5)+18=0

We multiply parentheses

-1x+4x-(2(-1x+5)+5)+12+18=0



We calculate terms in parentheses: -(2(-1x+5)+5), so:

2(-1x+5)+5

We multiply parentheses

-2x+10+5

We add all the numbers together, and all the variables

-2x+15

Back to the equation:

-(-2x+15)



We add all the numbers together, and all the variables

3x-(-2x+15)+30=0

We get rid of parentheses

3x+2x-15+30=0

We add all the numbers together, and all the variables

5x+15=0

We move all terms containing x to the left, all other terms to the right

5x=-15

x=-15/5

x=-3

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