(x-17)+(4x)=(9x-3)

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Solution for (x-17)+(4x)=(9x-3) equation: 



(x-17)+(4x)=(9x-3)

We move all terms to the left:

(x-17)+(4x)-((9x-3))=0

We add all the numbers together, and all the variables

4x+(x-17)-((9x-3))=0

We get rid of parentheses

4x+x-((9x-3))-17=0



We calculate terms in parentheses: -((9x-3)), so:

(9x-3)

We get rid of parentheses

9x-3

Back to the equation:

-(9x-3)



We add all the numbers together, and all the variables

5x-(9x-3)-17=0

We get rid of parentheses

5x-9x+3-17=0

We add all the numbers together, and all the variables

-4x-14=0

We move all terms containing x to the left, all other terms to the right

-4x=14

x=14/-4

x=-3+1/2

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