X=I(3i+2)

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Solution for X=I(3i+2) equation: 



X=(3X+2)

We move all terms to the left:

X-((3X+2))=0



We calculate terms in parentheses: -((3X+2)), so:

(3X+2)

We get rid of parentheses

3X+2

Back to the equation:

-(3X+2)



We get rid of parentheses

X-3X-2=0

We add all the numbers together, and all the variables

-2X-2=0

We move all terms containing X to the left, all other terms to the right

-2X=2

X=2/-2

X=-1

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