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(x-13)(x+8)=196
We move all terms to the left:
(x-13)(x+8)-(196)=0
We multiply parentheses ..
(+x^2+8x-13x-104)-196=0
We get rid of parentheses
x^2+8x-13x-104-196=0
We add all the numbers together, and all the variables
x^2-5x-300=0
a = 1; b = -5; c = -300;
Δ = b2-4ac
Δ = -52-4·1·(-300)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-35}{2*1}=\frac{-30}{2} =-15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+35}{2*1}=\frac{40}{2} =20 $
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