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16a-a2-64=0
We add all the numbers together, and all the variables
-1a^2+16a-64=0
a = -1; b = 16; c = -64;
Δ = b2-4ac
Δ = 162-4·(-1)·(-64)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$a=\frac{-b}{2a}=\frac{-16}{-2}=+8$
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