(x-10)+x2=425

Solution for (x-10)+x2=425 equation:

(x-10)+x2=425

We move all terms to the left:

(x-10)+x2-(425)=0

We add all the numbers together, and all the variables

x^2+(x-10)-425=0

We get rid of parentheses

x^2+x-10-425=0

We add all the numbers together, and all the variables

x^2+x-435=0

a = 1; b = 1; c = -435;
Δ = b2-4ac
Δ = 12-4·1·(-435)
Δ = 1741
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1741}}{2*1}=\frac{-1-\sqrt{1741}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1741}}{2*1}=\frac{-1+\sqrt{1741}}{2}
$