2(x+2)(x+1)=0

Solution for 2(x+2)(x+1)=0 equation:

2(x+2)(x+1)=0

We multiply parentheses ..

2(+x^2+x+2x+2)=0

We multiply parentheses

2x^2+2x+4x+4=0

We add all the numbers together, and all the variables

2x^2+6x+4=0

a = 2; b = 6; c = +4;
Δ = b2-4ac
Δ = 62-4·2·4
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2}{2*2}=\frac{-8}{4}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2}{2*2}=\frac{-4}{4}
=-1
$