(x-10)(x+10)=24

Solution for (x-10)(x+10)=24 equation:

(x-10)(x+10)=24

We move all terms to the left:

(x-10)(x+10)-(24)=0

We use the square of the difference formula

x^2-100-24=0

We add all the numbers together, and all the variables

x^2-124=0

a = 1; b = 0; c = -124;
Δ = b2-4ac
Δ = 02-4·1·(-124)
Δ = 496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{496}=\sqrt{16*31}=\sqrt{16}*\sqrt{31}=4\sqrt{31}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{31}}{2*1}=\frac{0-4\sqrt{31}}{2}
=-\frac{4\sqrt{31}}{2}
=-2\sqrt{31}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{31}}{2*1}=\frac{0+4\sqrt{31}}{2}
=\frac{4\sqrt{31}}{2}
=2\sqrt{31}
$