19f+1/5f=17f+2/7f

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Solution for 19f+1/5f=17f+2/7f equation:



19f+1/5f=17f+2/7f
We move all terms to the left:
19f+1/5f-(17f+2/7f)=0
Domain of the equation: 5f!=0
f!=0/5
f!=0
f∈R
Domain of the equation: 7f)!=0
f!=0/1
f!=0
f∈R
We add all the numbers together, and all the variables
19f+1/5f-(+17f+2/7f)=0
We get rid of parentheses
19f+1/5f-17f-2/7f=0
We calculate fractions
19f-17f+7f/35f^2+(-10f)/35f^2=0
We add all the numbers together, and all the variables
2f+7f/35f^2+(-10f)/35f^2=0
We multiply all the terms by the denominator
2f*35f^2+7f+(-10f)=0
We add all the numbers together, and all the variables
7f+2f*35f^2+(-10f)=0
Wy multiply elements
70f^3+7f+(-10f)=0
We get rid of parentheses
70f^3+7f-10f=0
We do not support efpression: f^3

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