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(x-1)(x-2x)=3
We move all terms to the left:
(x-1)(x-2x)-(3)=0
We add all the numbers together, and all the variables
(x-1)(-1x)-3=0
We multiply parentheses ..
(-1x^2+x)-3=0
We get rid of parentheses
-1x^2+x-3=0
a = -1; b = 1; c = -3;
Δ = b2-4ac
Δ = 12-4·(-1)·(-3)
Δ = -11
Delta is less than zero, so there is no solution for the equation
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