-2(5u-2)+5u=6+2(2u-4)

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Solution for -2(5u-2)+5u=6+2(2u-4) equation: 



-2(5u-2)+5u=6+2(2u-4)

We move all terms to the left:

-2(5u-2)+5u-(6+2(2u-4))=0

We add all the numbers together, and all the variables

5u-2(5u-2)-(6+2(2u-4))=0

We multiply parentheses

5u-10u-(6+2(2u-4))+4=0



We calculate terms in parentheses: -(6+2(2u-4)), so:

6+2(2u-4)

determiningTheFunctionDomain
2(2u-4)+6

We multiply parentheses

4u-8+6

We add all the numbers together, and all the variables

4u-2

Back to the equation:

-(4u-2)



We add all the numbers together, and all the variables

-5u-(4u-2)+4=0

We get rid of parentheses

-5u-4u+2+4=0

We add all the numbers together, and all the variables

-9u+6=0

We move all terms containing u to the left, all other terms to the right

-9u=-6

u=-6/-9

u=2/3

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