(x-1)(x+5)-(7x+13)=(x-4)(x+3)

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Solution for (x-1)(x+5)-(7x+13)=(x-4)(x+3) equation: 



(x-1)(x+5)-(7x+13)=(x-4)(x+3)

We move all terms to the left:

(x-1)(x+5)-(7x+13)-((x-4)(x+3))=0

We get rid of parentheses

(x-1)(x+5)-7x-((x-4)(x+3))-13=0

We multiply parentheses ..

(+x^2+5x-1x-5)-7x-((x-4)(x+3))-13=0



We calculate terms in parentheses: -((x-4)(x+3)), so:

(x-4)(x+3)

We multiply parentheses ..

(+x^2+3x-4x-12)

We get rid of parentheses

x^2+3x-4x-12

We add all the numbers together, and all the variables

x^2-1x-12

Back to the equation:

-(x^2-1x-12)



We get rid of parentheses

x^2-x^2+5x-1x-7x+1x-5+12-13=0

We add all the numbers together, and all the variables

-2x-6=0

We move all terms containing x to the left, all other terms to the right

-2x=6

x=6/-2

x=-3

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