4(n-3)-2(-3+n)=0

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Solution for 4(n-3)-2(-3+n)=0 equation: 



4(n-3)-2(-3+n)=0

We add all the numbers together, and all the variables

4(n-3)-2(n-3)=0

We multiply parentheses

4n-2n-12+6=0

We add all the numbers together, and all the variables

2n-6=0

We move all terms containing n to the left, all other terms to the right

2n=6

n=6/2

n=3

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