(x-1)(x+4)=(x-3)(x+3)

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Solution for (x-1)(x+4)=(x-3)(x+3) equation: 



(x-1)(x+4)=(x-3)(x+3)

We move all terms to the left:

(x-1)(x+4)-((x-3)(x+3))=0

We use the square of the difference formula

x^2+(x-1)(x+4)+9=0

We multiply parentheses ..

x^2+(+x^2+4x-1x-4)+9=0

We get rid of parentheses

x^2+x^2+4x-1x-4+9=0

We add all the numbers together, and all the variables

2x^2+3x+5=0

a = 2; b = 3; c = +5;
Δ = b2-4ac
Δ = 32-4·2·5
Δ = -31
Delta is less than zero, so there is no solution for the equation

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