2(x-2)-3(x+1)=7-(2x+5)

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Solution for 2(x-2)-3(x+1)=7-(2x+5) equation: 



2(x-2)-3(x+1)=7-(2x+5)

We move all terms to the left:

2(x-2)-3(x+1)-(7-(2x+5))=0

We multiply parentheses

2x-3x-(7-(2x+5))-4-3=0



We calculate terms in parentheses: -(7-(2x+5)), so:

7-(2x+5)

determiningTheFunctionDomain
-(2x+5)+7

We get rid of parentheses

-2x-5+7

We add all the numbers together, and all the variables

-2x+2

Back to the equation:

-(-2x+2)



We add all the numbers together, and all the variables

-1x-(-2x+2)-7=0

We get rid of parentheses

-1x+2x-2-7=0

We add all the numbers together, and all the variables

x-9=0

We move all terms containing x to the left, all other terms to the right

x=9

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