(x-1)(x+3)=(x+3)(x-7)

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Solution for (x-1)(x+3)=(x+3)(x-7) equation: 



(x-1)(x+3)=(x+3)(x-7)

We move all terms to the left:

(x-1)(x+3)-((x+3)(x-7))=0

We multiply parentheses ..

(+x^2+3x-1x-3)-((x+3)(x-7))=0



We calculate terms in parentheses: -((x+3)(x-7)), so:

(x+3)(x-7)

We multiply parentheses ..

(+x^2-7x+3x-21)

We get rid of parentheses

x^2-7x+3x-21

We add all the numbers together, and all the variables

x^2-4x-21

Back to the equation:

-(x^2-4x-21)



We get rid of parentheses

x^2-x^2+3x-1x+4x-3+21=0

We add all the numbers together, and all the variables

6x+18=0

We move all terms containing x to the left, all other terms to the right

6x=-18

x=-18/6

x=-3

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