3(2t-5)=30+-3t

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Solution for 3(2t-5)=30+-3t equation: 



3(2t-5)=30+-3t

We move all terms to the left:

3(2t-5)-(30+-3t)=0

We add all the numbers together, and all the variables

3(2t-5)-(-3t)=0

We multiply parentheses

6t-(-3t)-15=0

We get rid of parentheses

6t+3t-15=0

We add all the numbers together, and all the variables

9t-15=0

We move all terms containing t to the left, all other terms to the right

9t=15

t=15/9

t=1+2/3

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