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(x+x+1)+(2(x+2+x+3))=742
We move all terms to the left:
(x+x+1)+(2(x+2+x+3))-(742)=0
We add all the numbers together, and all the variables
(2x+1)+(2(2x+5))-742=0
We get rid of parentheses
2x+(2(2x+5))+1-742=0
We calculate terms in parentheses: +(2(2x+5)), so:We add all the numbers together, and all the variables
2(2x+5)
We multiply parentheses
4x+10
Back to the equation:
+(4x+10)
2x+(4x+10)-741=0
We get rid of parentheses
2x+4x+10-741=0
We add all the numbers together, and all the variables
6x-731=0
We move all terms containing x to the left, all other terms to the right
6x=731
x=731/6
x=121+5/6
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