5(3-4x)=7-(4+x)

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Solution for 5(3-4x)=7-(4+x) equation:



5(3-4x)=7-(4+x)
We move all terms to the left:
5(3-4x)-(7-(4+x))=0
We add all the numbers together, and all the variables
5(-4x+3)-(7-(x+4))=0
We multiply parentheses
-20x-(7-(x+4))+15=0
We calculate terms in parentheses: -(7-(x+4)), so:
7-(x+4)
determiningTheFunctionDomain -(x+4)+7
We get rid of parentheses
-x-4+7
We add all the numbers together, and all the variables
-1x+3
Back to the equation:
-(-1x+3)
We get rid of parentheses
-20x+1x-3+15=0
We add all the numbers together, and all the variables
-19x+12=0
We move all terms containing x to the left, all other terms to the right
-19x=-12
x=-12/-19
x=12/19

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