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(x+x)+(x+2)+(x+2)=(4x+4x)+(2x+2x)
We move all terms to the left:
(x+x)+(x+2)+(x+2)-((4x+4x)+(2x+2x))=0
We add all the numbers together, and all the variables
(+2x)+(x+2)+(x+2)-((+8x)+(+4x))=0
We get rid of parentheses
2x+x+x-((+8x)+(+4x))+2+2=0
We calculate terms in parentheses: -((+8x)+(+4x)), so:We add all the numbers together, and all the variables
(+8x)+(+4x)
We get rid of parentheses
8x+4x
We add all the numbers together, and all the variables
12x
Back to the equation:
-(12x)
-8x+4=0
We move all terms containing x to the left, all other terms to the right
-8x=-4
x=-4/-8
x=1/2
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