1=-8u+3(u+2)

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Solution for 1=-8u+3(u+2) equation:



1=-8u+3(u+2)
We move all terms to the left:
1-(-8u+3(u+2))=0
We calculate terms in parentheses: -(-8u+3(u+2)), so:
-8u+3(u+2)
We multiply parentheses
-8u+3u+6
We add all the numbers together, and all the variables
-5u+6
Back to the equation:
-(-5u+6)
We get rid of parentheses
5u-6+1=0
We add all the numbers together, and all the variables
5u-5=0
We move all terms containing u to the left, all other terms to the right
5u=5
u=5/5
u=1

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