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(x+9)(2x)=140
We move all terms to the left:
(x+9)(2x)-(140)=0
We multiply parentheses
2x^2+18x-140=0
a = 2; b = 18; c = -140;
Δ = b2-4ac
Δ = 182-4·2·(-140)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-38}{2*2}=\frac{-56}{4} =-14 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+38}{2*2}=\frac{20}{4} =5 $
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