0=4(2y-4y)+2y+-24

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Solution for 0=4(2y-4y)+2y+-24 equation: 



0=4(2y-4y)+2y+-24

We move all terms to the left:

0-(4(2y-4y)+2y+-24)=0

We add all the numbers together, and all the variables

-(4(-2y)+2y+-24)+0=0

We add all the numbers together, and all the variables

-(4(-2y)+2y+-24)=0

We use the square of the difference formula

-(4(-2y)+2y-24)=0



We calculate terms in parentheses: -(4(-2y)+2y-24), so:

4(-2y)+2y-24

We add all the numbers together, and all the variables

2y+4(-2y)-24

We multiply parentheses

2y-8y-24

We add all the numbers together, and all the variables

-6y-24

Back to the equation:

-(-6y-24)



We get rid of parentheses

6y+24=0

We move all terms containing y to the left, all other terms to the right

6y=-24

y=-24/6

y=-4

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