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(x+8)(x+8)=324
We move all terms to the left:
(x+8)(x+8)-(324)=0
We multiply parentheses ..
(+x^2+8x+8x+64)-324=0
We get rid of parentheses
x^2+8x+8x+64-324=0
We add all the numbers together, and all the variables
x^2+16x-260=0
a = 1; b = 16; c = -260;
Δ = b2-4ac
Δ = 162-4·1·(-260)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-36}{2*1}=\frac{-52}{2} =-26 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+36}{2*1}=\frac{20}{2} =10 $
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