(x+79)(9x-200)=0

Solution for (x+79)(9x-200)=0 equation:

(x+79)(9x-200)=0

We multiply parentheses ..

(+9x^2-200x+711x-15800)=0

We get rid of parentheses

9x^2-200x+711x-15800=0

We add all the numbers together, and all the variables

9x^2+511x-15800=0

a = 9; b = 511; c = -15800;
Δ = b2-4ac
Δ = 5112-4·9·(-15800)
Δ = 829921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{829921}=911$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(511)-911}{2*9}=\frac{-1422}{18}
=-79
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(511)+911}{2*9}=\frac{400}{18}
=22+2/9
$