(x+6)/6=1-(x+3)/5

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Solution for (x+6)/6=1-(x+3)/5 equation:



(x+6)/6=1-(x+3)/5
We move all terms to the left:
(x+6)/6-(1-(x+3)/5)=0
We calculate fractions
x/()+(-(1-(x+3)*6)/()=0
We calculate terms in parentheses: +(-(1-(x+3)*6)/(), so:
-(1-(x+3)*6)/(
We multiply all the terms by the denominator
-(1-(x+3)*6)
We calculate terms in parentheses: -(1-(x+3)*6), so:
1-(x+3)*6
determiningTheFunctionDomain -(x+3)*6+1
We multiply parentheses
-6x-18+1
We add all the numbers together, and all the variables
-6x-17
Back to the equation:
-(-6x-17)
We get rid of parentheses
6x+17
Back to the equation:
+(6x+17)
We get rid of parentheses
x/()+6x+17=0
We multiply all the terms by the denominator
x+6x*()+17*()=0
We add all the numbers together, and all the variables
x+6x*()=0

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