(x+54)+(3x)+(x-10)=x

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Solution for (x+54)+(3x)+(x-10)=x equation: 



(x+54)+(3x)+(x-10)=x

We move all terms to the left:

(x+54)+(3x)+(x-10)-(x)=0

We add all the numbers together, and all the variables

2x+(x+54)+(x-10)=0

We get rid of parentheses

2x+x+x+54-10=0

We add all the numbers together, and all the variables

4x+44=0

We move all terms containing x to the left, all other terms to the right

4x=-44

x=-44/4

x=-11

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