(x+5)/7=1-(x+3)/3

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Solution for (x+5)/7=1-(x+3)/3 equation: 



(x+5)/7=1-(x+3)/3

We move all terms to the left:

(x+5)/7-(1-(x+3)/3)=0

We calculate fractions


x/()+(-(1-(x+3)*7)/()=0



We calculate terms in parentheses: +(-(1-(x+3)*7)/(), so:

-(1-(x+3)*7)/(

We multiply all the terms by the denominator


-(1-(x+3)*7)



We calculate terms in parentheses: -(1-(x+3)*7), so:

1-(x+3)*7

determiningTheFunctionDomain
-(x+3)*7+1

We multiply parentheses

-7x-21+1

We add all the numbers together, and all the variables

-7x-20

Back to the equation:

-(-7x-20)



We get rid of parentheses

7x+20

Back to the equation:

+(7x+20)



We get rid of parentheses

x/()+7x+20=0

We multiply all the terms by the denominator


x+7x*()+20*()=0

We add all the numbers together, and all the variables

x+7x*()=0

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