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(x+5)+(x+5)+(2x+4)=4(2x+3)
We move all terms to the left:
(x+5)+(x+5)+(2x+4)-(4(2x+3))=0
We get rid of parentheses
x+x+2x-(4(2x+3))+5+5+4=0
We calculate terms in parentheses: -(4(2x+3)), so:We add all the numbers together, and all the variables
4(2x+3)
We multiply parentheses
8x+12
Back to the equation:
-(8x+12)
4x-(8x+12)+14=0
We get rid of parentheses
4x-8x-12+14=0
We add all the numbers together, and all the variables
-4x+2=0
We move all terms containing x to the left, all other terms to the right
-4x=-2
x=-2/-4
x=1/2
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