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(x+5)(x+2)-2(2x-3)=3x+2
We move all terms to the left:
(x+5)(x+2)-2(2x-3)-(3x+2)=0
We multiply parentheses
(x+5)(x+2)-4x-(3x+2)+6=0
We get rid of parentheses
(x+5)(x+2)-4x-3x-2+6=0
We multiply parentheses ..
(+x^2+2x+5x+10)-4x-3x-2+6=0
We add all the numbers together, and all the variables
(+x^2+2x+5x+10)-7x+4=0
We get rid of parentheses
x^2+2x+5x-7x+10+4=0
We add all the numbers together, and all the variables
x^2+14=0
a = 1; b = 0; c = +14;
Δ = b2-4ac
Δ = 02-4·1·14
Δ = -56
Delta is less than zero, so there is no solution for the equation
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