3(2x-5)+4(7-2x)=2x-3(2x-8)

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Solution for 3(2x-5)+4(7-2x)=2x-3(2x-8) equation: 



3(2x-5)+4(7-2x)=2x-3(2x-8)

We move all terms to the left:

3(2x-5)+4(7-2x)-(2x-3(2x-8))=0

We add all the numbers together, and all the variables

3(2x-5)+4(-2x+7)-(2x-3(2x-8))=0

We multiply parentheses

6x-8x-(2x-3(2x-8))-15+28=0



We calculate terms in parentheses: -(2x-3(2x-8)), so:

2x-3(2x-8)

We multiply parentheses

2x-6x+24

We add all the numbers together, and all the variables

-4x+24

Back to the equation:

-(-4x+24)



We add all the numbers together, and all the variables

-2x-(-4x+24)+13=0

We get rid of parentheses

-2x+4x-24+13=0

We add all the numbers together, and all the variables

2x-11=0

We move all terms containing x to the left, all other terms to the right

2x=11

x=11/2

x=5+1/2

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