(x+4)/4=5-(x+2)/3

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Solution for (x+4)/4=5-(x+2)/3 equation: 



(x+4)/4=5-(x+2)/3

We move all terms to the left:

(x+4)/4-(5-(x+2)/3)=0

We calculate fractions


x/()+(-(5-(x+2)*4)/()=0



We calculate terms in parentheses: +(-(5-(x+2)*4)/(), so:

-(5-(x+2)*4)/(

We multiply all the terms by the denominator


-(5-(x+2)*4)



We calculate terms in parentheses: -(5-(x+2)*4), so:

5-(x+2)*4

determiningTheFunctionDomain
-(x+2)*4+5

We multiply parentheses

-4x-8+5

We add all the numbers together, and all the variables

-4x-3

Back to the equation:

-(-4x-3)



We get rid of parentheses

4x+3

Back to the equation:

+(4x+3)



We get rid of parentheses

x/()+4x+3=0

We multiply all the terms by the denominator


x+4x*()+3*()=0

We add all the numbers together, and all the variables

x+4x*()=0

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