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3(x+3x)-(2+1)=-(4x+1)
We move all terms to the left:
3(x+3x)-(2+1)-(-(4x+1))=0
We add all the numbers together, and all the variables
3(+4x)-(-(4x+1))-3=0
We multiply parentheses
12x-(-(4x+1))-3=0
We calculate terms in parentheses: -(-(4x+1)), so:We get rid of parentheses
-(4x+1)
We get rid of parentheses
-4x-1
Back to the equation:
-(-4x-1)
12x+4x+1-3=0
We add all the numbers together, and all the variables
16x-2=0
We move all terms containing x to the left, all other terms to the right
16x=2
x=2/16
x=1/8
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