(x+4)/10=(x-2)/5

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Solution for (x+4)/10=(x-2)/5 equation: 



(x+4)/10=(x-2)/5

We move all terms to the left:

(x+4)/10-((x-2)/5)=0

We calculate fractions


x/()+(-((x-2)*10)/()=0



We calculate terms in parentheses: +(-((x-2)*10)/(), so:

-((x-2)*10)/(

We multiply all the terms by the denominator


-((x-2)*10)



We calculate terms in parentheses: -((x-2)*10), so:

(x-2)*10

We multiply parentheses

10x-20

Back to the equation:

-(10x-20)



We get rid of parentheses

-10x+20

Back to the equation:

+(-10x+20)



We get rid of parentheses

x/()-10x+20=0

We multiply all the terms by the denominator


x-10x*()+20*()=0

We add all the numbers together, and all the variables

x-10x*()=0

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