(x+4)+(3x+1)+(2x-1)=40

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Solution for (x+4)+(3x+1)+(2x-1)=40 equation: 



(x+4)+(3x+1)+(2x-1)=40

We move all terms to the left:

(x+4)+(3x+1)+(2x-1)-(40)=0

We get rid of parentheses

x+3x+2x+4+1-1-40=0

We add all the numbers together, and all the variables

6x-36=0

We move all terms containing x to the left, all other terms to the right

6x=36

x=36/6

x=6

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