(x+4)*(3x+1)*(2x-1)=40

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Solution for (x+4)*(3x+1)*(2x-1)=40 equation:



(x+4)(3x+1)(2x-1)=40
We move all terms to the left:
(x+4)(3x+1)(2x-1)-(40)=0
We multiply parentheses ..
(+3x^2+x+12x+4)(2x-1)-40=0
We move all terms containing x to the left, all other terms to the right
(+3x^2+x+12x+4)(2x-1)=40

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