(x+4)(x+1)=(x+7)(x-1)

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Solution for (x+4)(x+1)=(x+7)(x-1) equation: 



(x+4)(x+1)=(x+7)(x-1)

We move all terms to the left:

(x+4)(x+1)-((x+7)(x-1))=0

We multiply parentheses ..

(+x^2+x+4x+4)-((x+7)(x-1))=0



We calculate terms in parentheses: -((x+7)(x-1)), so:

(x+7)(x-1)

We multiply parentheses ..

(+x^2-1x+7x-7)

We get rid of parentheses

x^2-1x+7x-7

We add all the numbers together, and all the variables

x^2+6x-7

Back to the equation:

-(x^2+6x-7)



We get rid of parentheses

x^2-x^2+x+4x-6x+4+7=0

We add all the numbers together, and all the variables

-1x+11=0

We move all terms containing x to the left, all other terms to the right

-x=-11

x=-11/-1

x=+11

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