27-4z=3(z-5)

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Solution for 27-4z=3(z-5) equation: 



27-4z=3(z-5)

We move all terms to the left:

27-4z-(3(z-5))=0



We calculate terms in parentheses: -(3(z-5)), so:

3(z-5)

We multiply parentheses

3z-15

Back to the equation:

-(3z-15)



We get rid of parentheses

-4z-3z+15+27=0

We add all the numbers together, and all the variables

-7z+42=0

We move all terms containing z to the left, all other terms to the right

-7z=-42

z=-42/-7

z=+6

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