(x+3)2+(2x-6)2=26

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Solution for (x+3)2+(2x-6)2=26 equation: 



(x+3)2+(2x-6)2=26

We move all terms to the left:

(x+3)2+(2x-6)2-(26)=0

We multiply parentheses

2x+4x+6-12-26=0

We add all the numbers together, and all the variables

6x-32=0

We move all terms containing x to the left, all other terms to the right

6x=32

x=32/6

x=5+1/3

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