(x-1/x-2)-(x-2/x-3)=(x-5/x-6)

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Solution for (x-1/x-2)-(x-2/x-3)=(x-5/x-6) equation: 



(x-1/x-2)-(x-2/x-3)=(x-5/x-6)

We move all terms to the left:

(x-1/x-2)-(x-2/x-3)-((x-5/x-6))=0



Domain of the equation: x-2)!=0

x∈R





Domain of the equation: x-3)!=0

x∈R





Domain of the equation: x-6))!=0

x∈R



We get rid of parentheses

x-1/x-x+2/x-((x-5/x-6))-2+3=0

We calculate fractions


x-x+2x/x^2+(-((x-5*x)/x^2-2+3=0

We add all the numbers together, and all the variables

x-x+2x/x^2+(-((-4x)/x^2-2+3=0

We add all the numbers together, and all the variables

2x/x^2+(-((-4x)/x^2-2+3=0

We calculate fractions

We do not support expression: x^4

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