(x+3)/(1-x)=-9/x

Solution for (x+3)/(1-x)=-9/x equation:

(x+3)/(1-x)=-9/x

We move all terms to the left:

(x+3)/(1-x)-(-9/x)=0


Domain of the equation: (1-x)!=0

We move all terms containing x to the left, all other terms to the right

-x!=-1

x!=-1/-1

x!=1

x∈R



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(x+3)/(-1x+1)-(-9/x)=0

We get rid of parentheses

(x+3)/(-1x+1)+9/x=0

We calculate fractions


(x^2+3x)/(-1x^2+x)+(-9x+9)/(-1x^2+x)=0

We multiply all the terms by the denominator


(x^2+3x)+(-9x+9)=0

We get rid of parentheses

x^2+3x-9x+9=0

We add all the numbers together, and all the variables

x^2-6x+9=0

a = 1; b = -6; c = +9;
Δ = b2-4ac
Δ = -62-4·1·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{6}{2}=3$