12y-8(2y-1)=-20

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Solution for 12y-8(2y-1)=-20 equation: 



12y-8(2y-1)=-20

We move all terms to the left:

12y-8(2y-1)-(-20)=0

We add all the numbers together, and all the variables

12y-8(2y-1)+20=0

We multiply parentheses

12y-16y+8+20=0

We add all the numbers together, and all the variables

-4y+28=0

We move all terms containing y to the left, all other terms to the right

-4y=-28

y=-28/-4

y=+7

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