(x+3)+(x+2)+x=20

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Solution for (x+3)+(x+2)+x=20 equation: 



(x+3)+(x+2)+x=20

We move all terms to the left:

(x+3)+(x+2)+x-(20)=0

We add all the numbers together, and all the variables

x+(x+3)+(x+2)-20=0

We get rid of parentheses

x+x+x+3+2-20=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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