60/x+48=60/0.80x

Solution for 60/x+48=60/0.80x equation:

60/x+48=60/0.80x

We move all terms to the left:

60/x+48-(60/0.80x)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 0.80x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

60/x-(+60/0.80x)+48=0

We get rid of parentheses

60/x-60/0.80x+48=0

We calculate fractions


x/x^2+(-60x)/x^2+48=0

We multiply all the terms by the denominator


x+(-60x)+48*x^2=0

We add all the numbers together, and all the variables

48x^2+x+(-60x)=0

We get rid of parentheses

48x^2+x-60x=0

We add all the numbers together, and all the variables

48x^2-59x=0

a = 48; b = -59; c = 0;
Δ = b2-4ac
Δ = -592-4·48·0
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3481}=59$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-59}{2*48}=\frac{0}{96}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+59}{2*48}=\frac{118}{96}
=1+11/48
$