(x+3)+(2x-5)=78

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Solution for (x+3)+(2x-5)=78 equation: 



(x+3)+(2x-5)=78

We move all terms to the left:

(x+3)+(2x-5)-(78)=0

We get rid of parentheses

x+2x+3-5-78=0

We add all the numbers together, and all the variables

3x-80=0

We move all terms containing x to the left, all other terms to the right

3x=80

x=80/3

x=26+2/3

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