8y=3(y+4)+y

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Solution for 8y=3(y+4)+y equation: 



8y=3(y+4)+y

We move all terms to the left:

8y-(3(y+4)+y)=0



We calculate terms in parentheses: -(3(y+4)+y), so:

3(y+4)+y

We add all the numbers together, and all the variables

y+3(y+4)

We multiply parentheses

y+3y+12

We add all the numbers together, and all the variables

4y+12

Back to the equation:

-(4y+12)



We get rid of parentheses

8y-4y-12=0

We add all the numbers together, and all the variables

4y-12=0

We move all terms containing y to the left, all other terms to the right

4y=12

y=12/4

y=3

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