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(x+3)(6x+2)=180
We move all terms to the left:
(x+3)(6x+2)-(180)=0
We multiply parentheses ..
(+6x^2+2x+18x+6)-180=0
We get rid of parentheses
6x^2+2x+18x+6-180=0
We add all the numbers together, and all the variables
6x^2+20x-174=0
a = 6; b = 20; c = -174;
Δ = b2-4ac
Δ = 202-4·6·(-174)
Δ = 4576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4576}=\sqrt{16*286}=\sqrt{16}*\sqrt{286}=4\sqrt{286}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4\sqrt{286}}{2*6}=\frac{-20-4\sqrt{286}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4\sqrt{286}}{2*6}=\frac{-20+4\sqrt{286}}{12} $
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