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(x+3)(2x)=360
We move all terms to the left:
(x+3)(2x)-(360)=0
We multiply parentheses
2x^2+6x-360=0
a = 2; b = 6; c = -360;
Δ = b2-4ac
Δ = 62-4·2·(-360)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-54}{2*2}=\frac{-60}{4} =-15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+54}{2*2}=\frac{48}{4} =12 $
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